Adding 8 more holes to the heptomino set (plus one hole for the harbour heptomino) gives 765 unit squares, which can form (among other things) a 17x45 rectangle. Here's one with the holes arranged in a grid, like a little keypad for someone who doesn't mind not being able to type zeroes:
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| Fig. 2: 17x45 with 9 holes. | 
Taking the full set of heptominoes then removing the one with the hole leaves 107 pieces, which (since both 7 and 107) are prime can only make a 7x107 rectangle. Which has been done before, in loads of different ways (there's an example about half way down this page.) Below is a way I found, done as two 7x53's with the I-heptomino separating them.
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| Fig. 1: The heptominoes (excluding the holey one) in a 7x107 rectangle, with the I-heptomino right in the middle. Click for a full-size image, it's a little bit too long to fit on the page. | 
I also found this symmetric pinwheel shape, in response to the challenge about half way down Kadon Enterprises' page showing various heptomino solutions.
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| Fig. 3: A rotationally-symmetric shape with a central hole. | 
And just for funsies, here's a whopping cross made from all the pentominoes, hexominoes, and heptominoes combined:
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| Fig. 4: I need to just decide on one scale to draw every image in. And maybe pick a colour scheme and stick to that too, while I'm at it. | 
 
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